\(\tau=\tau_{\text{HB}}+\eta_{\text{HB}}{\dot{\gamma}}^{p}\) (1)
\(\tau_{\text{HB}}=56.86\text{Pa}\mathrm{,\ }\eta_{\text{HB}}=2.015\mathrm{,\ }p=0.7528\mathrm{,}{\ R}^{2}=1\) (2)